Эйлерийн арга

Чөлөөт нэвтэрхий толь — Википедиагаас
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Эйлерийн аргын ойролцооллын дүрслэл. Үл мэдэгдэх муруй нь хөх өнгөөр, улаан өнгөөр муруйг ойролцоолсон дөхөлтүүдийг тэмдэглэв.

Математик болон тооцон бодох шинжлэх ухаанд, Эйлерийн арга нь анхны утга өгөгдсөн ердийн дифференциал тэгшитгэлийг (ODEs) шийдэхэд хэрэглэгдэх SN эрэмбийн тоон арга юм. It is the most basic дифференциал тэгшитгэлийг тоон аргаар интеграцлахад хамгийн энгийн бөгөөд тохиромжит ил арга бөгөөд Рунге-Куттагийн арга-ын хялбар хэлбэр юм. Энэ арга нь Леонард Эйлерийн нэрээр нэрлэгдсэн ба, анх түүний Institutionum calculi integralis гэдэг номонд ашиглагдсан байна. ( 1768–70 онд хэвлэгдсэн).[1]

Ойролцоолох үед гарах бодолтын алдаа (алхам дахь алдаа) нь алхамын хэмжээний квадраттай пропорциональ, нийлбэр алдаа нь (өгөгдсөн хугацаан дахь алдаа) нь хугацааны алхамтай профорциональ учир энэ арга нь нэгдүгээр эрэмбийн арга юм. Эйлерийн арга нь илүү нарийвчлал болон өндөр эрэмбийн комплекс аргийг цогцлооход үндэс суурь нь болж өгдөг.

Энгийн геометр дүрслэл[засварлах | кодоор засах]

Consider the problem of calculating the shape of an unknown curve which starts at a given point and satisfies a given differential equation. Here, a differential equation can be thought of as a formula by which the slope of the tangent line to the curve can be computed at any point on the curve, once the position of that point has been calculated.

The idea is that while the curve is initially unknown, its starting point, which we denote by is known (see the picture on top right). Then, from the differential equation, the slope to the curve at can be computed, and so, the tangent line.

Take a small step along that tangent line up to a point Along this small step, the slope does not change too much, so will be close to the curve. If we pretend that is still on the curve, the same reasoning as for the point above can be used. After several steps, a polygonal curve is computed. In general, this curve does not diverge too far from the original unknown curve, and the error between the two curves can be made small if the step size is small enough and the interval of computation is finite.[2]

Аргын томъёолол[засварлах | кодоор засах]

Suppose that we want to approximate the solution of the initial value problem

Choose a value for the size of every step and set . Now, one step of the Euler method from to is[3]

The value of is an approximation of the solution to the ODE at time : . The Euler method is explicit, i.e. the solution is an explicit function of for .

While the Euler method integrates a first-order ODE, any ODE of order N can be represented as a first-order ODE: to treat the equation


we introduce auxiliary variables and obtain the equivalent equation

This is a first-order system in the variable and can be handled by Euler's method or, in fact, by any other scheme for first-order systems.[4]

Жишээ[засварлах | кодоор засах]

Given the initial value problem

we would like to use the Euler method to approximate .[5]

Алхамын хэмжээг 1-тэй тэнцүү гэж үзэх (h = 1)[засварлах | кодоор засах]

Illustration of numerical integration for the equation Blue is the Euler method; green, the midpoint method; red, the exact solution, The step size is h = 1.0.

The Euler method is

so first we must compute . In this simple differential equation, the function is defined by . We have

By doing the above step, we have found the slope of the line that is tangent to the solution curve at the point . Recall that the slope is defined as the change in divided by the change in , or .

The next step is to multiply the above value by the step size , which we take equal to one here:

Since the step size is the change in , when we multiply the step size and the slope of the tangent, we get a change in value. This value is then added to the initial value to obtain the next value to be used for computations.

The above steps should be repeated to find , and .

Due to the repetitive nature of this algorithm, it can be helpful to organize computations in a chart form, as seen below, to avoid making errors.

0 1 0 1 1 1 2
1 2 1 2 1 2 4
2 4 2 4 1 4 8
3 8 3 8 1 8 16

The conclusion of this computation is that . The exact solution of the differential equation is , so . Thus, the approximation of the Euler method is not very good in this case. However, as the figure shows, its behaviour is qualitatively right.

Өөр алхамын хэмжээ ашиглах[засварлах | кодоор засах]

The same illustration for h = 0.25.

As suggested in the introduction, the Euler method is more accurate if the step size is smaller. The table below shows the result with different step sizes. The top row corresponds to the example in the previous section, and the second row is illustrated in the figure.

step size result of Euler's method error
1 16 38.598
0.25 35.53 19.07
0.1 45.26 9.34
0.05 49.56 5.04
0.025 51.98 2.62
0.0125 53.26 1.34

The error recorded in the last column of the table is the difference between the exact solution at and the Euler approximation. In the bottom of the table, the step size is half the step size in the previous row, and the error is also approximately half the error in the previous row. This suggests that the error is roughly proportional to the step size, at least for fairly small values of the step size. This is true in general, also for other equations; see the section Global truncation error for more details.

Other methods, such as the midpoint method also illustrated in the figures, behave more favourably: the error of the midpoint method is roughly proportional to the square of the step size. For this reason, the Euler method is said to be a first-order method, while the midpoint method is second order.

We can extrapolate from the above table that the step size needed to get an answer that is correct to three decimal places is approximately 0.00001, meaning that we need 400,000 steps. This large number of steps entails a high computational cost. For this reason, people usually employ alternative, higher-order methods such as Runge–Kutta methods or linear multistep methods, especially if a high accuracy is desired.[6]

Гаргалгаа[засварлах | кодоор засах]

The Euler method can be derived in a number of ways. Firstly, there is the geometrical description mentioned above.

Another possibility is to consider the Taylor expansion of the function around :

The differential equation states that . If this is substituted in the Taylor expansion and the quadratic and higher-order terms are ignored, the Euler method arises.[7] The Taylor expansion is used below to analyze the error committed by the Euler method, and it can be extended to produce Runge–Kutta methods.

A closely related derivation is to substitute the forward finite difference formula for the derivative,

in the differential equation . Again, this yields the Euler method.[8] A similar computation leads to the midpoint rule and the backward Euler method.

Finally, one can integrate the differential equation from to and apply the fundamental theorem of calculus to get:

Now approximate the integral by the left-hand rectangle method (with only one rectangle):

Combining both equations, one finds again the Euler method.[9] This line of thought can be continued to arrive at various linear multistep methods.

Орчны хасалтын алдаа[засварлах | кодоор засах]

The local truncation error of the Euler method is error made in a single step. It is the difference between the numerical solution after one step, , and the exact solution at time . The numerical solution is given by

For the exact solution, we use the Taylor expansion mentioned in the section Derivation above:

The local truncation error (LTE) introduced by the Euler method is given by the difference between these equations:

This result is valid if has a bounded third derivative.[10]

This shows that for small , the local truncation error is approximately proportional to . This makes the Euler method less accurate (for small ) than other higher-order techniques such as Runge-Kutta methods and linear multistep methods, for which the local truncation error is proportial to a higher power of the step size.

A slightly different formulation for the local truncation error can be obtained by using the Lagrange form for the remainder term in Taylor's theorem. If has a continuous second derivative, then there exists a such that


In the above expressions for the error, the second derivative of the unknown exact solution can be replaced by an expression involving the right-hand side of the differential equation. Indeed, it follows from the equation that


Нийт хасалтын алдаа[засварлах | кодоор засах]

The global truncation error is the error at a fixed time , after however many steps the methods needs to take to reach that time from the initial time. The global truncation error is the cumulative effect of the local truncation errors committed in each step.[13] The number of steps is easily determined to be , which is proportional to , and the error committed in each step is proportional to (see the previous section). Thus, it is to be expected that the global truncation error will be proportional to .[14]

This intuitive reasoning can be made precise. If the solution has a bounded second derivative and is Lipschitz continuous in its second argument, then the global truncation error (GTE) is bounded by

where is an upper bound on the second derivative of on the given interval and is the Lipschitz constant of .[15]

The precise form of this bound of little practical importance, as in most cases the bound vastly overestimates the actual error committed by the Euler method.[16] What is important is that it shows that the global truncation error is (approximately) proportional to . For this reason, the Euler method is said to be first order.[17]

Тооцооллын тогтворшилт[засварлах | кодоор засах]

Solution of computed with the Euler method with step size (blue squares) and (red circles). The black curve shows the exact solution.

The Euler method can also be numerically unstable, especially for stiff equations, meaning that the numerical solution grows very large for equations where the exact solution does not. This can be illustrated using the linear equation

The exact solution is , which decays to zero as . However, if the Euler method is applied to this equation with step size , then the numerical solution is qualitatively wrong: it oscillates and grows (see the figure). This is what it means to be unstable. If a smaller step size is used, for instance , then the numerical solution does decay to zero.

The pink disk shows the stability region for the Euler method.

If the Euler method is applied to the linear equation , then the numerical solution is unstable if the product is outside the region

illustrated on the right. This region is called the (linear) instability region.[18] In the example, equals −2.3, so if then which is outside the stability region, and thus the numerical solution is unstable.

This limitation —along with its slow convergence of error with h— means that the Euler method is not often used, except as a simple example of numerical integration.

Алдааны тойрог[засварлах | кодоор засах]

The discussion up to now has ignored the consequences of rounding error. In step n of the Euler method, the rounding error is roughly of the magnitude εyn where ε is the machine epsilon. Assuming that the rounding errors are all of approximately the same size, the combined rounding error in N steps is roughly Nεy0 if all errors points in the same direction. Since the number of steps is inversely proportional to the step size h, the total rounding error is proportional to ε / h. In reality, however, it is extremely unlikely that all rounding errors point in the same direction. If instead it is assumed that the rounding errors are independent rounding variables, then the total rounding error is proportional to .[19]

Thus, for extremely small values of the step size, the truncation error will be small but the effect of rounding error may be big. Most of the effect of rounding error can be easily avoided if compensated summation is used in the formula for the Euler method.[20]

Сайжруулалт ба өргөтгөл[засварлах | кодоор засах]

A simple modification of the Euler method which eliminates the stability problems noted in the previous section is the backward Euler method:

This differs from the (standard, or forward) Euler method in that the function is evaluated at the end point of the step, instead of the starting point. The backward Euler method is an implicit method, meaning that the formula for the backward Euler method has on both sides, so when applying the backward Euler method we have to solve an equation. This makes the implementation more costly.

Other modifications of the Euler method that help with stability yield the exponential Euler method or the semi-implicit Euler method.

More complicated methods can achieve a higher order (and more accuracy). One possibility is to use more function evaluations. This is illustrated by the midpoint method which is already mentioned in this article:

This leads to the family of Runge–Kutta methods.

The other possibility is to use more past values, as illustrated by the two-step Adams–Bashforth method:

This leads to the family of linear multistep methods.

Мөн үзэх[засварлах | кодоор засах]

Тэмдэглэл[засварлах | кодоор засах]

Лавлах[засварлах | кодоор засах]

Гадаад холбоос[засварлах | кодоор засах]

Wikibooks: Euler's Method – Сурах бичиг, зааврууд

Загвар:Тоон интеграцлагч